3.6.69 \(\int \frac {(d+e x)^7 (f+g x)^2}{(d^2-e^2 x^2)^3} \, dx\) [569]

Optimal. Leaf size=179 \[ -\frac {d \left (7 e^2 f^2+48 d e f g+56 d^2 g^2\right ) x}{e^2}-\frac {(e f+2 d g) (e f+12 d g) x^2}{2 e}-\frac {1}{3} g (2 e f+7 d g) x^3-\frac {1}{4} e g^2 x^4+\frac {8 d^4 (e f+d g)^2}{e^3 (d-e x)^2}-\frac {32 d^3 (e f+d g) (e f+2 d g)}{e^3 (d-e x)}-\frac {8 d^2 \left (3 e^2 f^2+14 d e f g+13 d^2 g^2\right ) \log (d-e x)}{e^3} \]

[Out]

-d*(56*d^2*g^2+48*d*e*f*g+7*e^2*f^2)*x/e^2-1/2*(2*d*g+e*f)*(12*d*g+e*f)*x^2/e-1/3*g*(7*d*g+2*e*f)*x^3-1/4*e*g^
2*x^4+8*d^4*(d*g+e*f)^2/e^3/(-e*x+d)^2-32*d^3*(d*g+e*f)*(2*d*g+e*f)/e^3/(-e*x+d)-8*d^2*(13*d^2*g^2+14*d*e*f*g+
3*e^2*f^2)*ln(-e*x+d)/e^3

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Rubi [A]
time = 0.16, antiderivative size = 179, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.069, Rules used = {862, 90} \begin {gather*} \frac {8 d^4 (d g+e f)^2}{e^3 (d-e x)^2}-\frac {32 d^3 (d g+e f) (2 d g+e f)}{e^3 (d-e x)}-\frac {d x \left (56 d^2 g^2+48 d e f g+7 e^2 f^2\right )}{e^2}-\frac {8 d^2 \left (13 d^2 g^2+14 d e f g+3 e^2 f^2\right ) \log (d-e x)}{e^3}-\frac {1}{3} g x^3 (7 d g+2 e f)-\frac {x^2 (2 d g+e f) (12 d g+e f)}{2 e}-\frac {1}{4} e g^2 x^4 \end {gather*}

Antiderivative was successfully verified.

[In]

Int[((d + e*x)^7*(f + g*x)^2)/(d^2 - e^2*x^2)^3,x]

[Out]

-((d*(7*e^2*f^2 + 48*d*e*f*g + 56*d^2*g^2)*x)/e^2) - ((e*f + 2*d*g)*(e*f + 12*d*g)*x^2)/(2*e) - (g*(2*e*f + 7*
d*g)*x^3)/3 - (e*g^2*x^4)/4 + (8*d^4*(e*f + d*g)^2)/(e^3*(d - e*x)^2) - (32*d^3*(e*f + d*g)*(e*f + 2*d*g))/(e^
3*(d - e*x)) - (8*d^2*(3*e^2*f^2 + 14*d*e*f*g + 13*d^2*g^2)*Log[d - e*x])/e^3

Rule 90

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.)*((e_.) + (f_.)*(x_))^(p_.), x_Symbol] :> Int[ExpandI
ntegrand[(a + b*x)^m*(c + d*x)^n*(e + f*x)^p, x], x] /; FreeQ[{a, b, c, d, e, f, p}, x] && IntegersQ[m, n] &&
(IntegerQ[p] || (GtQ[m, 0] && GeQ[n, -1]))

Rule 862

Int[((d_) + (e_.)*(x_))^(m_)*((f_.) + (g_.)*(x_))^(n_)*((a_) + (c_.)*(x_)^2)^(p_.), x_Symbol] :> Int[(d + e*x)
^(m + p)*(f + g*x)^n*(a/d + (c/e)*x)^p, x] /; FreeQ[{a, c, d, e, f, g, m, n}, x] && NeQ[e*f - d*g, 0] && EqQ[c
*d^2 + a*e^2, 0] && (IntegerQ[p] || (GtQ[a, 0] && GtQ[d, 0] && EqQ[m + p, 0]))

Rubi steps

\begin {align*} \int \frac {(d+e x)^7 (f+g x)^2}{\left (d^2-e^2 x^2\right )^3} \, dx &=\int \frac {(d+e x)^4 (f+g x)^2}{(d-e x)^3} \, dx\\ &=\int \left (-\frac {d \left (7 e^2 f^2+48 d e f g+56 d^2 g^2\right )}{e^2}+\frac {(-e f-12 d g) (e f+2 d g) x}{e}-g (2 e f+7 d g) x^2-e g^2 x^3+\frac {32 d^3 (-e f-2 d g) (e f+d g)}{e^2 (d-e x)^2}-\frac {16 d^4 (e f+d g)^2}{e^2 (-d+e x)^3}-\frac {8 d^2 \left (3 e^2 f^2+14 d e f g+13 d^2 g^2\right )}{e^2 (-d+e x)}\right ) \, dx\\ &=-\frac {d \left (7 e^2 f^2+48 d e f g+56 d^2 g^2\right ) x}{e^2}-\frac {(e f+2 d g) (e f+12 d g) x^2}{2 e}-\frac {1}{3} g (2 e f+7 d g) x^3-\frac {1}{4} e g^2 x^4+\frac {8 d^4 (e f+d g)^2}{e^3 (d-e x)^2}-\frac {32 d^3 (e f+d g) (e f+2 d g)}{e^3 (d-e x)}-\frac {8 d^2 \left (3 e^2 f^2+14 d e f g+13 d^2 g^2\right ) \log (d-e x)}{e^3}\\ \end {align*}

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Mathematica [A]
time = 0.06, size = 193, normalized size = 1.08 \begin {gather*} -\frac {d \left (7 e^2 f^2+48 d e f g+56 d^2 g^2\right ) x}{e^2}-\frac {\left (e^2 f^2+14 d e f g+24 d^2 g^2\right ) x^2}{2 e}-\frac {1}{3} g (2 e f+7 d g) x^3-\frac {1}{4} e g^2 x^4+\frac {8 d^4 (e f+d g)^2}{e^3 (d-e x)^2}+\frac {32 d^3 \left (e^2 f^2+3 d e f g+2 d^2 g^2\right )}{e^3 (-d+e x)}-\frac {8 d^2 \left (3 e^2 f^2+14 d e f g+13 d^2 g^2\right ) \log (d-e x)}{e^3} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[((d + e*x)^7*(f + g*x)^2)/(d^2 - e^2*x^2)^3,x]

[Out]

-((d*(7*e^2*f^2 + 48*d*e*f*g + 56*d^2*g^2)*x)/e^2) - ((e^2*f^2 + 14*d*e*f*g + 24*d^2*g^2)*x^2)/(2*e) - (g*(2*e
*f + 7*d*g)*x^3)/3 - (e*g^2*x^4)/4 + (8*d^4*(e*f + d*g)^2)/(e^3*(d - e*x)^2) + (32*d^3*(e^2*f^2 + 3*d*e*f*g +
2*d^2*g^2))/(e^3*(-d + e*x)) - (8*d^2*(3*e^2*f^2 + 14*d*e*f*g + 13*d^2*g^2)*Log[d - e*x])/e^3

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Maple [A]
time = 0.09, size = 216, normalized size = 1.21

method	result	size
default	\(-\frac {\frac {1}{4} g^{2} e^{3} x^{4}+\frac {7}{3} d \,e^{2} g^{2} x^{3}+\frac {2}{3} e^{3} f g \,x^{3}+12 d^{2} e \,g^{2} x^{2}+7 d \,e^{2} f g \,x^{2}+\frac {1}{2} e^{3} f^{2} x^{2}+56 d^{3} g^{2} x +48 d^{2} e f g x +7 d \,e^{2} f^{2} x}{e^{2}}-\frac {32 d^{3} \left (2 d^{2} g^{2}+3 d e f g +e^{2} f^{2}\right )}{e^{3} \left (-e x +d \right )}+\frac {8 d^{4} \left (d^{2} g^{2}+2 d e f g +e^{2} f^{2}\right )}{e^{3} \left (-e x +d \right )^{2}}-\frac {8 d^{2} \left (13 d^{2} g^{2}+14 d e f g +3 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{e^{3}}\)	\(216\)
risch	\(-\frac {e \,g^{2} x^{4}}{4}-\frac {7 x^{3} d \,g^{2}}{3}-\frac {2 e \,x^{3} f g}{3}-\frac {12 x^{2} d^{2} g^{2}}{e}-7 x^{2} d f g -\frac {e \,x^{2} f^{2}}{2}-\frac {56 d^{3} g^{2} x}{e^{2}}-\frac {48 d^{2} f g x}{e}-7 d \,f^{2} x +\frac {\left (64 d^{5} g^{2}+96 d^{4} e f g +32 d^{3} e^{2} f^{2}\right ) x -\frac {8 d^{4} \left (7 d^{2} g^{2}+10 d e f g +3 e^{2} f^{2}\right )}{e}}{e^{2} \left (-e x +d \right )^{2}}-\frac {104 d^{4} \ln \left (-e x +d \right ) g^{2}}{e^{3}}-\frac {112 d^{3} \ln \left (-e x +d \right ) f g}{e^{2}}-\frac {24 d^{2} \ln \left (-e x +d \right ) f^{2}}{e}\)	\(216\)
norman	\(\frac {\left (\frac {521}{3} d^{5} g^{2}+\frac {574}{3} d^{4} e f g +46 d^{3} e^{2} f^{2}\right ) x^{3}+\left (-\frac {154}{3} g^{2} d^{3} e^{2}-\frac {140}{3} f g \,e^{3} d^{2}-7 f^{2} d \,e^{4}\right ) x^{5}+\left (-\frac {23}{2} g^{2} e^{3} d^{2}-7 f g d \,e^{4}-\frac {1}{2} f^{2} e^{5}\right ) x^{6}-\frac {d^{4} \left (319 g^{2} e \,d^{4}+376 f g \,d^{3} e^{2}+100 f^{2} e^{3} d^{2}\right )}{4 e^{4}}-\frac {g^{2} e^{5} x^{8}}{4}+\frac {d^{2} \left (215 g^{2} e \,d^{4}+266 f g \,d^{3} e^{2}+83 f^{2} e^{3} d^{2}\right ) x^{2}}{2 e^{2}}-\frac {d^{5} \left (104 d^{2} g^{2}+112 d e f g +23 e^{2} f^{2}\right ) x}{e^{2}}-\frac {e^{4} g \left (7 d g +2 e f \right ) x^{7}}{3}}{\left (-e^{2} x^{2}+d^{2}\right )^{2}}-\frac {8 d^{2} \left (13 d^{2} g^{2}+14 d e f g +3 e^{2} f^{2}\right ) \ln \left (-e x +d \right )}{e^{3}}\)	\(297\)

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((e*x+d)^7*(g*x+f)^2/(-e^2*x^2+d^2)^3,x,method=_RETURNVERBOSE)

[Out]

-1/e^2*(1/4*g^2*e^3*x^4+7/3*d*e^2*g^2*x^3+2/3*e^3*f*g*x^3+12*d^2*e*g^2*x^2+7*d*e^2*f*g*x^2+1/2*e^3*f^2*x^2+56*
d^3*g^2*x+48*d^2*e*f*g*x+7*d*e^2*f^2*x)-32*d^3/e^3*(2*d^2*g^2+3*d*e*f*g+e^2*f^2)/(-e*x+d)+8*d^4*(d^2*g^2+2*d*e
*f*g+e^2*f^2)/e^3/(-e*x+d)^2-8*d^2*(13*d^2*g^2+14*d*e*f*g+3*e^2*f^2)*ln(-e*x+d)/e^3

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Maxima [A]
time = 0.29, size = 218, normalized size = 1.22 \begin {gather*} -8 \, {\left (13 \, d^{4} g^{2} + 14 \, d^{3} f g e + 3 \, d^{2} f^{2} e^{2}\right )} e^{\left (-3\right )} \log \left (x e - d\right ) - \frac {1}{12} \, {\left (3 \, g^{2} x^{4} e^{3} + 4 \, {\left (7 \, d g^{2} e^{2} + 2 \, f g e^{3}\right )} x^{3} + 6 \, {\left (24 \, d^{2} g^{2} e + 14 \, d f g e^{2} + f^{2} e^{3}\right )} x^{2} + 12 \, {\left (56 \, d^{3} g^{2} + 48 \, d^{2} f g e + 7 \, d f^{2} e^{2}\right )} x\right )} e^{\left (-2\right )} - \frac {8 \, {\left (7 \, d^{6} g^{2} + 10 \, d^{5} f g e + 3 \, d^{4} f^{2} e^{2} - 4 \, {\left (2 \, d^{5} g^{2} e + 3 \, d^{4} f g e^{2} + d^{3} f^{2} e^{3}\right )} x\right )}}{x^{2} e^{5} - 2 \, d x e^{4} + d^{2} e^{3}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^7*(g*x+f)^2/(-e^2*x^2+d^2)^3,x, algorithm="maxima")

[Out]

-8*(13*d^4*g^2 + 14*d^3*f*g*e + 3*d^2*f^2*e^2)*e^(-3)*log(x*e - d) - 1/12*(3*g^2*x^4*e^3 + 4*(7*d*g^2*e^2 + 2*
f*g*e^3)*x^3 + 6*(24*d^2*g^2*e + 14*d*f*g*e^2 + f^2*e^3)*x^2 + 12*(56*d^3*g^2 + 48*d^2*f*g*e + 7*d*f^2*e^2)*x)
*e^(-2) - 8*(7*d^6*g^2 + 10*d^5*f*g*e + 3*d^4*f^2*e^2 - 4*(2*d^5*g^2*e + 3*d^4*f*g*e^2 + d^3*f^2*e^3)*x)/(x^2*
e^5 - 2*d*x*e^4 + d^2*e^3)

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Fricas [A]
time = 4.08, size = 322, normalized size = 1.80 \begin {gather*} -\frac {672 \, d^{6} g^{2} + {\left (3 \, g^{2} x^{6} + 8 \, f g x^{5} + 6 \, f^{2} x^{4}\right )} e^{6} + 2 \, {\left (11 \, d g^{2} x^{5} + 34 \, d f g x^{4} + 36 \, d f^{2} x^{3}\right )} e^{5} + {\left (91 \, d^{2} g^{2} x^{4} + 416 \, d^{2} f g x^{3} - 162 \, d^{2} f^{2} x^{2}\right )} e^{4} + 4 \, {\left (103 \, d^{3} g^{2} x^{3} - 267 \, d^{3} f g x^{2} - 75 \, d^{3} f^{2} x\right )} e^{3} - 48 \, {\left (25 \, d^{4} g^{2} x^{2} + 12 \, d^{4} f g x - 6 \, d^{4} f^{2}\right )} e^{2} - 96 \, {\left (d^{5} g^{2} x - 10 \, d^{5} f g\right )} e + 96 \, {\left (13 \, d^{6} g^{2} + 3 \, d^{2} f^{2} x^{2} e^{4} + 2 \, {\left (7 \, d^{3} f g x^{2} - 3 \, d^{3} f^{2} x\right )} e^{3} + {\left (13 \, d^{4} g^{2} x^{2} - 28 \, d^{4} f g x + 3 \, d^{4} f^{2}\right )} e^{2} - 2 \, {\left (13 \, d^{5} g^{2} x - 7 \, d^{5} f g\right )} e\right )} \log \left (x e - d\right )}{12 \, {\left (x^{2} e^{5} - 2 \, d x e^{4} + d^{2} e^{3}\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^7*(g*x+f)^2/(-e^2*x^2+d^2)^3,x, algorithm="fricas")

[Out]

-1/12*(672*d^6*g^2 + (3*g^2*x^6 + 8*f*g*x^5 + 6*f^2*x^4)*e^6 + 2*(11*d*g^2*x^5 + 34*d*f*g*x^4 + 36*d*f^2*x^3)*
e^5 + (91*d^2*g^2*x^4 + 416*d^2*f*g*x^3 - 162*d^2*f^2*x^2)*e^4 + 4*(103*d^3*g^2*x^3 - 267*d^3*f*g*x^2 - 75*d^3
*f^2*x)*e^3 - 48*(25*d^4*g^2*x^2 + 12*d^4*f*g*x - 6*d^4*f^2)*e^2 - 96*(d^5*g^2*x - 10*d^5*f*g)*e + 96*(13*d^6*
g^2 + 3*d^2*f^2*x^2*e^4 + 2*(7*d^3*f*g*x^2 - 3*d^3*f^2*x)*e^3 + (13*d^4*g^2*x^2 - 28*d^4*f*g*x + 3*d^4*f^2)*e^
2 - 2*(13*d^5*g^2*x - 7*d^5*f*g)*e)*log(x*e - d))/(x^2*e^5 - 2*d*x*e^4 + d^2*e^3)

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Sympy [A]
time = 0.75, size = 219, normalized size = 1.22 \begin {gather*} - \frac {8 d^{2} \cdot \left (13 d^{2} g^{2} + 14 d e f g + 3 e^{2} f^{2}\right ) \log {\left (- d + e x \right )}}{e^{3}} - \frac {e g^{2} x^{4}}{4} - x^{3} \cdot \left (\frac {7 d g^{2}}{3} + \frac {2 e f g}{3}\right ) - x^{2} \cdot \left (\frac {12 d^{2} g^{2}}{e} + 7 d f g + \frac {e f^{2}}{2}\right ) - x \left (\frac {56 d^{3} g^{2}}{e^{2}} + \frac {48 d^{2} f g}{e} + 7 d f^{2}\right ) - \frac {56 d^{6} g^{2} + 80 d^{5} e f g + 24 d^{4} e^{2} f^{2} + x \left (- 64 d^{5} e g^{2} - 96 d^{4} e^{2} f g - 32 d^{3} e^{3} f^{2}\right )}{d^{2} e^{3} - 2 d e^{4} x + e^{5} x^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)**7*(g*x+f)**2/(-e**2*x**2+d**2)**3,x)

[Out]

-8*d**2*(13*d**2*g**2 + 14*d*e*f*g + 3*e**2*f**2)*log(-d + e*x)/e**3 - e*g**2*x**4/4 - x**3*(7*d*g**2/3 + 2*e*
f*g/3) - x**2*(12*d**2*g**2/e + 7*d*f*g + e*f**2/2) - x*(56*d**3*g**2/e**2 + 48*d**2*f*g/e + 7*d*f**2) - (56*d
**6*g**2 + 80*d**5*e*f*g + 24*d**4*e**2*f**2 + x*(-64*d**5*e*g**2 - 96*d**4*e**2*f*g - 32*d**3*e**3*f**2))/(d*
*2*e**3 - 2*d*e**4*x + e**5*x**2)

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Giac [A]
time = 1.80, size = 215, normalized size = 1.20 \begin {gather*} -8 \, {\left (13 \, d^{4} g^{2} + 14 \, d^{3} f g e + 3 \, d^{2} f^{2} e^{2}\right )} e^{\left (-3\right )} \log \left ({\left | x e - d \right |}\right ) - \frac {1}{12} \, {\left (3 \, g^{2} x^{4} e^{13} + 28 \, d g^{2} x^{3} e^{12} + 144 \, d^{2} g^{2} x^{2} e^{11} + 672 \, d^{3} g^{2} x e^{10} + 8 \, f g x^{3} e^{13} + 84 \, d f g x^{2} e^{12} + 576 \, d^{2} f g x e^{11} + 6 \, f^{2} x^{2} e^{13} + 84 \, d f^{2} x e^{12}\right )} e^{\left (-12\right )} - \frac {8 \, {\left (7 \, d^{6} g^{2} + 10 \, d^{5} f g e + 3 \, d^{4} f^{2} e^{2} - 4 \, {\left (2 \, d^{5} g^{2} e + 3 \, d^{4} f g e^{2} + d^{3} f^{2} e^{3}\right )} x\right )} e^{\left (-3\right )}}{{\left (x e - d\right )}^{2}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((e*x+d)^7*(g*x+f)^2/(-e^2*x^2+d^2)^3,x, algorithm="giac")

[Out]

-8*(13*d^4*g^2 + 14*d^3*f*g*e + 3*d^2*f^2*e^2)*e^(-3)*log(abs(x*e - d)) - 1/12*(3*g^2*x^4*e^13 + 28*d*g^2*x^3*
e^12 + 144*d^2*g^2*x^2*e^11 + 672*d^3*g^2*x*e^10 + 8*f*g*x^3*e^13 + 84*d*f*g*x^2*e^12 + 576*d^2*f*g*x*e^11 + 6
*f^2*x^2*e^13 + 84*d*f^2*x*e^12)*e^(-12) - 8*(7*d^6*g^2 + 10*d^5*f*g*e + 3*d^4*f^2*e^2 - 4*(2*d^5*g^2*e + 3*d^
4*f*g*e^2 + d^3*f^2*e^3)*x)*e^(-3)/(x*e - d)^2

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Mupad [B]
time = 0.14, size = 375, normalized size = 2.09 \begin {gather*} \frac {x\,\left (64\,d^5\,g^2+96\,d^4\,e\,f\,g+32\,d^3\,e^2\,f^2\right )-\frac {8\,\left (7\,d^6\,g^2+10\,d^5\,e\,f\,g+3\,d^4\,e^2\,f^2\right )}{e}}{d^2\,e^2-2\,d\,e^3\,x+e^4\,x^2}-x^2\,\left (\frac {6\,d^2\,e^2\,g^2+8\,d\,e^3\,f\,g+e^4\,f^2}{2\,e^3}-\frac {3\,d^2\,g^2}{2\,e}+\frac {3\,d\,\left (2\,g\,\left (2\,d\,g+e\,f\right )+3\,d\,g^2\right )}{2\,e}\right )-x\,\left (\frac {d^3\,g^2}{e^2}-\frac {3\,d^2\,\left (2\,g\,\left (2\,d\,g+e\,f\right )+3\,d\,g^2\right )}{e^2}+\frac {4\,d\,\left (d^2\,g^2+3\,d\,e\,f\,g+e^2\,f^2\right )}{e^2}+\frac {3\,d\,\left (\frac {6\,d^2\,e^2\,g^2+8\,d\,e^3\,f\,g+e^4\,f^2}{e^3}-\frac {3\,d^2\,g^2}{e}+\frac {3\,d\,\left (2\,g\,\left (2\,d\,g+e\,f\right )+3\,d\,g^2\right )}{e}\right )}{e}\right )-x^3\,\left (\frac {2\,g\,\left (2\,d\,g+e\,f\right )}{3}+d\,g^2\right )-\frac {\ln \left (e\,x-d\right )\,\left (104\,d^4\,g^2+112\,d^3\,e\,f\,g+24\,d^2\,e^2\,f^2\right )}{e^3}-\frac {e\,g^2\,x^4}{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(((f + g*x)^2*(d + e*x)^7)/(d^2 - e^2*x^2)^3,x)

[Out]

(x*(64*d^5*g^2 + 32*d^3*e^2*f^2 + 96*d^4*e*f*g) - (8*(7*d^6*g^2 + 3*d^4*e^2*f^2 + 10*d^5*e*f*g))/e)/(d^2*e^2 +
e^4*x^2 - 2*d*e^3*x) - x^2*((e^4*f^2 + 6*d^2*e^2*g^2 + 8*d*e^3*f*g)/(2*e^3) - (3*d^2*g^2)/(2*e) + (3*d*(2*g*(
2*d*g + e*f) + 3*d*g^2))/(2*e)) - x*((d^3*g^2)/e^2 - (3*d^2*(2*g*(2*d*g + e*f) + 3*d*g^2))/e^2 + (4*d*(d^2*g^2
+ e^2*f^2 + 3*d*e*f*g))/e^2 + (3*d*((e^4*f^2 + 6*d^2*e^2*g^2 + 8*d*e^3*f*g)/e^3 - (3*d^2*g^2)/e + (3*d*(2*g*(
2*d*g + e*f) + 3*d*g^2))/e))/e) - x^3*((2*g*(2*d*g + e*f))/3 + d*g^2) - (log(e*x - d)*(104*d^4*g^2 + 24*d^2*e^
2*f^2 + 112*d^3*e*f*g))/e^3 - (e*g^2*x^4)/4

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